Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value that is the same as the immediately preceding value is considered a CONSECUTIVE DUPLICATE. In this example, there are three such consecutive duplicates: the 2nd and 3rd 5s and the second 6. Note that the last 3 is not a consecutive duplicate because it was preceded by a 7. Write some code that uses a loop to read such a sequence of non-negative integers, terminated by a negative number. When the code exits the loop it should print the number of consecutive duplicates encountered. In the above case, that value would be 3.

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Click on the title for the solution
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This is the answer:

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int firstNumber,secondNumber = -1, duplicates = 0;
do {
cin >> firstNumber;
if ( secondNumber == -1) {
secondNumber = firstNumber;
}else {
if ( secondNumber == firstNumber )
duplicates++;
else
secondNumber = firstNumber;
}
} while(firstNumber > 0 );

cout << duplicates;

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