Declare k, d, and s so that they can store an integer, a real number, and a small word (under 10 characters). Use these variables to first read in an integer, a real number, and a small word and print them out in reverse order (i.e., the word, the real, and then the integer) all on the same line, separated by EXACTLY one space from each other. Then, on a second line, print them out in the original order (the integer, the real, and the word), separated again by EXACTLY one space from each other.

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Click on the title for the solution
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This is the answer:

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int k;
double d;
string s;
cin>>k>>d>>s;
cout<<s<<" "<<d<<" "<<k<<endl<<k<<" "<<d<<" "<<s;

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. . Click on the title for the solution . . This is the answer: : #include <iostream> #include <fstream> #include <string> using namespace std; void lookup(); void add(); int main() { string type; while (cin >> type) { if (type == "lookup") lookup(); else  add(); } return 0; } void lookup() { ifstream fin; fin.open("phonedir"); if(!fin.is_open()) cout << "Not Open" << endl; bool check = false; string name,firstName,lastName,email; cin >> name; while (fin >> firstName >> lastName >> email) { if (firstName== name || lastName==name) { cout<<firstName<<" "<<lastName<<" "<<email<<endl; check=true; } } if(!check) cout << name << ": not found" << endl; fin.close(); } void add() { ofstream fout; string name; string fir...
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