Given an int variable i that has already been declared, write a for loop that prints the integers 0 through 39, separated by spaces. Use no variables other than i.

By -
.
.
Click on the title for the solution
.
.

This is the answer:

:



for(i=0;i<40;i++) cout<< i<<' ';

Comments

Post a Comment

Popular posts from this blog

411: You are given a file named phonedir that consists of many lines containing three strings: lastname firstname emailaddress. Write a utility program that reads commands (from stdin). Each command has one of two possible forms: lookup string add lastname firstname emailaddress In the case of the first command (lookup), the program looks for a line in the phonedir file where either the firstname or lastname matches the string given. If it finds such a line it prints out all three parts of the line, separated by spaces: lastname firstname emailaddress If it does not find a match in the file it prints out the string it was looking for, followed by a colon followed by a space followed by the message "not found": string: not found In the case of the second command (add), the program appends the three strings given to the file phonedir. Hints and suggestions: (1) Define and use two functions named lookup and add. When your program reads the string lookup, your lookup function is called; when the program reads the string add, your add function is called. When either of these two functions are called, they then read whatever else is necessary for their command (one string for lookup and three strings -- lastname, firstname, and emailaddress-- for add). And then these functions do... whatever it takes to carry out the command. (2) When doing a lookup or an add, open up the file phonedir ... carry out the operation .. and then close up the file. EXAMPLE: suppose the phonedir file looked like this: arnow david arnow@panix.com bush george president@whitehouse.gov gates bill bill@microsoft.com here then is a sample session with the program (program output is in bold): lookup david arnow david arnow@panix.com lookup joe joe: not found add theplumber joe joetheplumber@nowhere.com lookup arnow arnow david arnow@panix.com lookup joe theplumber joe joetheplumber@nowhere.com and the phonedir file would now be: arnow david arnow@panix.com bush george president@whitehouse.gov gates bill bill@microsoft.com theplumber joe joetheplumber@nowhere.com

By Author -
. . Click on the title for the solution . . This is the answer: : #include <iostream> #include <fstream> #include <string> using namespace std; void lookup(); void add(); int main() { string type; while (cin >> type) { if (type == "lookup") lookup(); else  add(); } return 0; } void lookup() { ifstream fin; fin.open("phonedir"); if(!fin.is_open()) cout << "Not Open" << endl; bool check = false; string name,firstName,lastName,email; cin >> name; while (fin >> firstName >> lastName >> email) { if (firstName== name || lastName==name) { cout<<firstName<<" "<<lastName<<" "<<email<<endl; check=true; } } if(!check) cout << name << ": not found" << endl; fin.close(); } void add() { ofstream fout; string name; string fir...
Read more

Assume a class Window with accessor method getWidth that accepts no parameters and returns an integer. Assume further an array of 3 Window elements named winarr, has been declared and initialized. Write a sequence of statements that prints out the width of the widest window in the array.

By -
. . Click on the title for the solution . . This is the answer: : int max_width = winarr[0].getWidth(); if (winarr[0].getWidth()==winarr[1].getWidth() &&  winarr[1].getWidth()==winarr[2].getWidth()) cout<<"0"; if (max_width < winarr[1].getWidth()) cout<<winarr[1].getWidth(); if (max_width < winarr[2].getWidth()) cout<<winarr[2].getWidth(); if (max_width>winarr[1].getWidth() && max_width>winarr[2].getWidth()) cout<< winarr[0].getWidth();
Read more